Question

Question: find an equation of a parabola that satisfies the given condition

Problem: horizontal axis; vertex (-1,2) passing through (2,3)

Answer 1

Final Ans : y = 1/9(x + 1)^2 +2

Step-by-step explanation:

Given
Vertex (-1,2) and passes (2,3)
The General equation of a parabola is
y = a(x - h)^2 + k
So, y = a(x+1)^2 +2
still now we need to find (a)

by the second point (2,3)
we have 3=a(2+1)^2 + 2
3= 9a +2
a = 1/9

Therefore the final answer is
y = 1/9(x + 1)^2 +2

Good Luck.