How many Joules of energy are contained in a photon-with 2 = 496.36 nm?

asked Nov 21, 2022 96.4k views

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2 votes

We know

$\boxed{\sf E=hv=(hc)/(\lambda)}$

$\\ \sf\longmapsto E=(6.626* 10^(-34)Js* 3* 10^8ms^(-1))/(496.36* 10^(-9)m)$

$\\ \sf\longmapsto E=0.004* 10^(-17)J$

$\\ \sf\longmapsto E=0.04* 10^(-16)$

$\\ \sf\longmapsto E=0.04eJ$

Feerlay answered Nov 28, 2022

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