Question

A ball thrown horizontally from a point 53.8 m above the ground, strikes the ground after traveling horizontally a distance of 98.3 m. Assuming negligible air resistance, the initial speed of the ball is

Answer 1

Step-by-step explanation:

Assuming the ground is horizontal

The time the vertical distance is covered from rest is

t = √(2s/g)

t = √(2(53.8 / 9.81)

t = 3.311857... 3.31 s

v = d/t = 98.3/3.31

v = 29.681...

v = 29.7 m/s