Question

Help Me On This Plss!!​

Answer 1

1) In fig. (1) there are 2 shapes:

1. A Rectangle
2. A triangle

So,

Area of Rectangle = l × b

where,

• length (l) = 12 cm
• breadth (b) = 14 cm

➮ 12 × 14

➮ 168

Hence, the area of rectangle is 168cm².

Now,

Area of Triangle = ½bh

where,

• base (b) = 8 cm
• height (h) = 12 cm

➮ ½ × 8 × 12

➮ ½ × 96

➮ 48

Hence, the area of triangle is 48cm².

Thus, Area of the whole fig. :

Area of Rectangle + Area of Triangle

➮ 168 + 48

➮ 216cm² (Ans)

2) In fig. (2) there are also 2 shapes :

1. A Semicircle
2. A Rectangle

So,

Area of Semicircle = ½ (πr²)

where,

• pi (π) = 3.14
• radius (r) = 5 inches

➮ ½ × 3.14 × (5)²

➮ ½ × 3.14 × 25

➮ ½ × 78.5

➮ 39.25

Hence, the area of semicircle is 39.25 in².

Now,

Area of Rectangle = l × b

where,

• length (l) = 10 inches
• breadth (b) = 15 inches

➮ 10 × 15

➮ 150

Hence, the area of rectangle is 150 in².

Thus, Area of whole fig. :

Area of Semicircle + Area of Rectangle

➮ 39.25 + 150

➮ 189.25 in² (Ans)

Answer 2

`\bold{\huge{\underline{ Solutions }}}`

Figure 1 :-

Given :-

• We have one composite figure that is composed rectangle and triangle
• The dimensions of rectangle are 12 cm and 14 cm
• The dimensions of triangle are 12cm and 8cm

To Find :-

• We have to find the area of composite figure

Let's Begin :-

We have,

• Composite figure composed of rectangle and triangle

We know that,

Area of rectangle

`\bold{ = Length {*} Breath}`

• The dimensions of rectangle are 12cm and 14cm

Subsitute the required values,

`\sf{ = 12 {*} 14}`

`\sf{ = 168 \: cm^(2)}`

For triangle

Area of triangle

`\bold{=}{\bold{( 1)/(2)}}{\bold{ {*} b{*}h}}`

Subsitute the required values,

`\sf{=}{\sf{( 1)/(2)}}{\bold{ {*}8{*}12}}`

`\sf{=}{\sf{( 1)/(2)}}{\bold{ {*} 96}}`

`\sf{ = 48 \:cm^(2)}`

Thus, Area of triangle is 48 cm² .

Therefore,

The total area of the composite figure

= Area of rectangle + Area of triangle

`\sf{ = 168 + 48}`

`\bold{ = 216\: cm^(2)}`

Hence, The area of given composite figure is 216 cm²

Figure 2 :-

Given :-

• We have one composite figure which is composed of semicircle and rectangle
• The dimensions of rectangle are 10 in. and 15 in.
• The diameter of semicircle is 10 in.

Let's Begin :-

Here, we have

• Composite figure composed of rectangle and hemisphere

We know that,

Area of rectangle

`\bold{ = Length {*} Breath}`

• The dimensions of rectangle are 10in. and 15 in.

Subsitute the required values,

`\sf{ = 10 {*} 15}`

`\sf{ = 150 \: cm^(2)}`

For hemisphere

Area of semicircle

`\bold{ = 1/2{\pi}r^(2)}`

• The diameter of hemisphere is 10 in.
• So, The radius of hemisphere will be 5 in. as it is the half of diameter.

Subsitute the required values,

`\sf{ =}{\sf{( 1)/(2 )}}{\sf{ {*} 3.14 {*} (5)^(2)}}`

`\sf{ = }{\sf{(1)/(2)}}{\sf{ {*}3.14 {*} 25}}`

`\sf{ = 1.57 {*} 25}`

`\sf{ = 39.25\: in^(2)}`

Thus, The area of semicircle is 39.25 in².

Therefore,

Total area of the given composite figure

= Area of hemisphere + Area of rectangle

=
`\sf{ = 150 + 39.25}`

`\bold{ = 189.25\: in^(2)}`

Hence, The total area of the given composite figure is 189.25 in² .