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2 votes
Show that (sec A - tan A)² = 1-sinA/1+sinA



User Radarek
by
8.4k points

1 Answer

3 votes

Answer:

LHS=(secA−tanA)

2

=(

cosA

1

cosA

sinA

)

2

=

(1−sin

2

A)

(1−sinA)

2

=

(1−sinA)(1+sinA)

(1−sinA)

2

=

1+sinA

1−sinA

=RHS

Hence proved.

User Simon Arnold
by
8.1k points

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