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Solve the simultaneous equation y = x^2 and y = 3x - 2

User Sharel
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Answer:


{x}^(2) = 3x - 2 \\ {x}^(2) - 3x + 2 = 0 \\ (x - 1)(x - 2) = 0 \\ x = 1 \: or \: x = 2 \\ for \: x \: = 1 \\ \: y = {(1)}^(2) = 1 \\ for \: x = 2 \\ y = {(2)}^(2) = 4

User Gkunz
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