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Algebra 2 help needed asap

Algebra 2 help needed asap-example-1

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Answer:

The number of beads Emery uses to calculate how many 4 necklaces and 7 bracelets are 152 beads.

Explanation:

This is a simultaneous equation.

let's make n the number of necklaces, and b the number of bracelets.

8n + 3b = 172. 1st equation

1n + 5b = 77. 2nd equation.

you have to make one of the Bs or the Ns the same.

I chose B. it doesn't matter which side you choose.

40n + 15b =860. I multiplied by 5

3n + 15b =231. I multiplied by 3

then you subtract. because the signs are the same.

40n - 3n = 37n, 15n - 15n = 0, 860 - 231 = 629

37n =629. we divide both sides by 37

n = 17. one necklace has a total of 17 beads.

we substitute to find the number of bracelets (b).

choose any of the 1st or 2nd equations.

1n + 5b = 77

(17) + 5b = 77

5b = 77- 17

5b = 60

b = 12. one bracelet has a total of 12 beads.

NOW: find how many beads Emery uses to calculate how many 4 necklaces and 7 bracelets.

equation: 4n + 7b = ?

4(17) + 7(12) = 152

which means there are 152 beads.

YOU SHOULD BE GRATEFUL. :D

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