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2 votes
What is the elastic potential energy of a spring with a 80 N/m spring constant

that has been moved 0. 6 m from equilibrium?

User Dan Mantyla
by
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1 Answer

19 votes
19 votes
Elastic potential energy
=1/2k(change in x^2)
=1/2(80)(0.6^2)
=14.4J

User SteveMellross
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