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Find the 15th term of the arithmetic sequence 2x+7, 6x+11, 10x+15,

User Roy Holzem
by
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1 Answer

4 votes

Answer:

a15 = 58x + 63

Explanation:

number of terms (n) = 15

first term (a1) = 2x + 7

second term (a2) = 6x + 11

common difference (d) = a2-a1 = 6x + 11 - (2x + 7)

= 6x + 11 - 2x - 7

= 4x + 4

= 4(x + 1)

15th term (a15) = ?

equation :

a15 = a1 + (n - 1) × d

a15 = 2x + 7 + (15 - 1) × 4(x + 1)

a15 = 2x + 7 + 14 × 4 × (x + 1)

a15 = 2x + 7 + 56(x + 1)

a15 = 2x + 7 + 56x + 56

a15 = 58x + 63

User Cjquinn
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