Answer:
n(B∪C) = 6
Explanation:
Given the following sets:
B = {d, p, q, z}
C = {v, w, x, y, z}
We can use the Addition Principle for Counting:
n(B∪C) = n(B) + n (C) - n(B∩C):
where:
n(B) is the number of elements in set B,
n(C) = number of elements in set C,
n(B∩C) = the intersection of sets B and C.
Cardinal number or cardinality is defined as the number of elements in a set.
Looking into the given sets, the similar elements between sets B and C is z, (cardinality = 1). This similar element represents the n(B∩C).
The cardinal number of set B represented by n(B), is the number of distinct elements in set B. Therefore, the cardinality of n(B) = 3
And the cardinality of set c, n(C) = 4
Plugging in these values into the Addition Counting Principle:
n(B∪C) = n(B) + n (C) - n(B∩C)
n(B∪C) = 3 + 4 - 1
n(B∪C) = 6
Attached is the Venn diagram that represents the elments in sets B and C, and the n(B∩C) = z = 1.