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A constant acceleration of 0.25 m/s^2, how long would it take to attain a

speed of 45 m/s at which speed it could liftoff?

1 Answer

1 vote

Answer:

180 s

Step-by-step explanation:

a= v-u/t

0.25=45-0/t

t=45/0.25

t=180 s

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