Question

Can someone help me with this please?

Answer 1

bbbbb

Explanation:

Answer 2

Answer: See below

Explanation:

`\begin{bmatrix}y=x^2-20x+73\\ y=-3x+3\end{bmatrix}`

`\mathrm{Subtract\:the\:equations:}`

`y=x^2-20x+73`

`-`

`\underline{y=-3x+3}`

`y-y=x^2-20x+73-\left(-3x+3\right)`

`\mathrm{Simplify:}`

`0=x^2-17x+70`

`x^2-17x+70=0`

`\mathrm{Solve\:with\:the\:quadratic\:formula}`
`\mathrm{for\:}\ a=1,\:b=-17,\:c=70:`

`x_(1,\:2)=(-\left(-17\right)\pm √(\left(-17\right)^2-4\cdot \:1\cdot \:70))/(2\cdot \:1)`

`x_(1,\:2)=(-\left(-17\right)\pm \:3)/(2\cdot \:1)`

`\mathrm{Separate\:the\:solutions:}`

`x_1=(-\left(-17\right)+3)/(2\cdot \:1),\:x_2=(-\left(-17\right)-3)/(2\cdot \:1)`

`\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}`

`x=10,\:x=7`

`\mathrm{Plug\:the\:solutions\:}x=10,\:x=7\mathrm{\:into\:}y=x^2-20x+73:`

`\mathrm{For\:}y=x^2-20x+73\mathrm{,\:subsitute\:}x\mathrm{\:with\:}10`

`y=10^2-20\cdot \:10+73`

`y=10^2-200+73`

`y=100-127`

`y=-27`

`\mathrm{For\:}y=x^2-20x+73\mathrm{,\:subsitute\:}x\mathrm{\:with\:}7`

`y=7^2-20\cdot \:7+73`

`y=7^2-140+73`

`y=49-67`

`y=-18`

`\mathrm{Therefore,\:the\:final\:solutions\:for\:}y=x^2-20x+73,\:y=-3x+3\mathrm{\:are\:}:`

`\begin{pmatrix}x=10,\:&y=-27\\ x=7,\:&y=-18\end{pmatrix}`