Question

Determine the molecular formula for a compound that contains 89.94% C and the rest H, when the molecular mass is 120.2 amu.​

Answer 1

C9H9

Step-by-step explanation:

C. H

89.94. 10.06

• divide each by their mass number

89.94/12. 10.06/1

7.495. 10.06

• divide both by smallest

7.495/7.495. 10.06/7.495

1. :. 1

empirical formula=CH

(CH)n=120.2

(12+1)n=120.2

13n=120.2

n=120.2/13

n=9.

molecular formula=C9H9