Question

darren is proving that the slopr between any two points on a straight line is the same. He has already proved that triangles 1 and 2 are similar. Drag statements and reasons to complete the proof​

Answer 1

Explanation:

Slope of a line = (y₂ - y₁)/(x₂ - x₁)

K' = y₂ - y₁ ( for E & F)

L' = x₂ - x₁ ( for E & F)

=> Slope from E to F = K'/L'

Two triangles are similar

=> K/K' = L/L' = DE/EF

=> K/K' = L/L'

=> K/L = K'/L'

=> K'/L' = K/L

Triangles are similar

K - L = K' - L'

Sufficient information is not given but from picture it is clear that slope of line = 1

=> K = L & K' = L'

hence K - L = 0 & K' - L' = 0

=> K - L = K' - L'

Answer 2

Answer: For the last Statement Answer is K/L = K/L