Question

Calculate the distance between the points E=(-2,5) and H=(1, -3) in the coordinate plane.

Round your answer to the nearest hundredth.

Answer 1

The distance between points E and H is 8.49 rounded to the nearest hundreths.

Explanation:

You use the distance formula

d=√( (x2-x1)²+(y2-y1)²)

You plug in the points of E and H into the formula where -2 of point E is X1 and 5 of point is is Y1. 1 of point H is X2 and -3 of point H is Y2.

That would look like:

1. d=√( (x2-x1)²+(y2-y1)²)

2. d=√( (1- -2)²+(-3-5)²)

3. d=√( (3)²+(-8)²)

4. d=√ (9+64)

5. √72

Then you'd plug the square root of 72 (√72) into the calculator to get 8.485281374.

If you round it to the nearest hundredth you get 8. 49

Hope you understand. Comment if you don't.