Answer:
a) (6, 6) and (7, 4)
b)
![t(n)=-2n+18](https://img.qammunity.org/2023/formulas/mathematics/college/1ci2t8bzmqsrjtwkvuyn35n5jg4twyp1zj.png)
c) see attached
Explanation:
From inspection of the table, we can see that as n increases by 2, t(n) decreases by 4. Therefore, as this a directly proportional relationship, it is a linear function.
So as n increases by 1, t(n) will decrease by 2.
Therefore, the remaining two ordered pairs are:
(6, 6)
(7, 4)
We know that the function decreases by 2 each time n increases by 1, so the slope (gradient) of the linear function will be -2.
Using the point-slope formula:
![y-y_1=m(x-x_1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/csobd57zth7rh9k4hz9amldzpq2owf0z4j.png)
(where
is the slope and
is a point on the line)
Given:
![\implies y-16=-2(x-1)](https://img.qammunity.org/2023/formulas/mathematics/college/aiqj0fpzk40en7x4c5wue545lx24iat2tn.png)
![\implies y=-2x+18](https://img.qammunity.org/2023/formulas/mathematics/college/mqysq12rvid1fbl1zykiryn6h9l9gkkvrz.png)
![\implies t(n)=-2n+18](https://img.qammunity.org/2023/formulas/mathematics/college/up498uqa189krm8jh56lqt8n4cgvh8qz0p.png)
Graphing
To find the y-intercept, substitute
into the equation:
![\implies t(0)=-2(0)+18=18](https://img.qammunity.org/2023/formulas/mathematics/college/vhbjzmni5x23ajfismkualwgh1ev84ihuu.png)
Therefore, the y-intercept is (0, 18)
To find where the line crosses the x-axis, set the equation to zero and solve for n:
![\implies -2n+18=0](https://img.qammunity.org/2023/formulas/mathematics/college/yl22xgh3re13jsenaknov7ehr3zgnjccvh.png)
![\implies 2n=18](https://img.qammunity.org/2023/formulas/mathematics/college/d7z13wx127wsaucjouai71fkqu1zsodqes.png)
![\implies n=9](https://img.qammunity.org/2023/formulas/mathematics/college/fufosmnp6ejw9gvp70qng3gnfif3jr5wae.png)
Therefore, the line crosses the x-axis at (9, 0)