Explanation:
are (x1,y1) and (x2,y2) is
d=(y2−y1)+(x2−x1)2
Let (3,−1)=(x1,y1) and (6, 5) = =(x2,y2)
∴ d = (y2−y1)+(x2−x1)2
= (6)2+(3)2=36+9
= 45=9×5=35
So length of the line segment whose end
point are (3, -1) and (6, 5) is 35
5.1m questions
6.7m answers