Question

What is an equation of the line that passes through the points (4, 4) and (8,1)?

Answer 1

Explanation:

first find the slope with m=
`(y2-y1)/(x2-x1) \\`

M =
`(y2-y1)/(x2-x1)` =
`(1-4)/(8-4)` =
`(-3)/(4)` ← SLOPE

then add in one of the points so I am using (4, 4)

Y = mx+b

4 =
`(-3)/(4)`(4)+b

4 = -3 + b

add 3 to both sides

7=b

then add those two answers into the y=mx+b formula so it would be

Y=
`(-3)/(4)` x + 7