Question

Suppose we have a triangle with vertices located at A(-6,-3), B(2,5), and C(8,-3). Where is the

vertex C' located if the figure is translated 4 units to the left and 3 units down?

Answer 1

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Answer:

C'(4, -6)

Explanation:

Translation right by h and up by k is described by ...

(x, y) ⇒ (x +h, y +k)

Here, you have 4 left and 3 down, so (h, k) = (-4, -3) and the transformation is ...

(x, y) ⇒ (x -4, y -3)

C(8, -3) ⇒ C'(8 -4, -3 -3) = C'(4, -6)