Question

What is the equation of the linear function y-3=1/5(x-3) in standard form?

Answer 1

X=30 thats what i got

Answer 2

x - 5y = -12 or 1x - 5y = -12

Explanation:

The standard form is Ax + By = C

Where, if at all possible, A, B, and C are integers, and A is non-negative.

Given the linear function,
`y - 3 = (1)/(5)(x - 3)`, we must transform this equation into its standard form.

We can start by distributing 1/5 into the terms inside the parenthesis:

• y - 3 = 1/5x - 3/5

Subtract 1/5x on both sides of the equation:

• y - 3 - 1/5x = 1/5x - 3/5 - 1/5x

This will result in:

• y - 3 - 1/5x = -3/5

Next, add 3 on both sides of the equation:

• y - 3 - 1/5x + 3 = -3/5 + 3

• - 1/5x + y = 3 - 3/5

Simplify the like terms on the right-hand side of the equation:

• -1/5x + y = 12/5

We can eliminate the fractions and turn the coefficient of x (A) into a positive number by multiplying both sides of the equation by -5:

• -5(-1/5x + y) = (12/5) (-5)

Our linear equation in standard form is:

x - 5y = -12 or 1x - 5y = -12

where A = 1, B = -5, and C = -12