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In a 1.125E2 g sample of iron(III) oxide, how many grams of iron are present?

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Answer: 78.69 g of Fe

Explanation: Iron(III) oxide is Fe2O3. It has a molar mass of 159.7 g/mole. That consists of:

2 x Fe at 55.85 = 11.69 or 69.94%

3 x O at 16.0 = 48.0 or 30.06%

Therefore 112.5 grams will contain (112.5 g)*(69.94%) = 78.69 g of Fe

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