Question

What is the product?
2y 4-12
y-3 2y+ 6

Answer 1

`\displaystyle (4y)/(y+3)`

Explanation:

Hi there!

`\displaystyle (2y)/(y-3)*(4y-12)/(2y+6)`

Factor the second fraction:

`= \displaystyle (2y)/(y-3)*(4(y-3))/(2(y+3))`

Simplify:

`= \displaystyle (2y)/(y-3)*(2(y-3))/((y+3))`

Multiply:

`= \displaystyle (2y*2(y-3))/((y-3)(y+3))\\\\= \displaystyle (4y(y-3))/((y-3)(y+3))`

Simplify:

`= \displaystyle (4y)/(y+3)`

I hope this helps!