91.1k views
5 votes
given an oil droplet of mass 0.9mg and density 918kg/m^3 that spreads out into a circle of a radius 41.8cm on the water surface what is the diameter of the oil molecule​

User Tenobaal
by
7.9k points

1 Answer

3 votes

Answer:

The diameter of the oil molecule is .

Step-by-step explanation:

Mass of the oil drop =

Density of the oil drop =

Volume of the oil drop: v

Thickness of the oil drop is 1 molecule thick.So, let the thickness of the drop or diameter of the molecule be x.

Radius of the oil drop on the water surface,r = 41.8 cm = 0.418 m

1 cm = 0.01 m

Surface of the sphere is given as: a =

Volume of the oil drop = v = Area × thickness

The thickness of the oil drop is and so is the diameter of the molecule.

User Starling
by
8.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.