Question

If m2WXY =160º, what are m2WXZ and mZZXY?
Z
(5x+2)
(77-4)
w

Answer 1

87, 73 (solution A)

Explanation:

We know that angle WXY is 160 degrees. Therefore, (5x+8)+(7x-4)=160.

(5x+8)+(7x-4)=160

5x+8+7x-4=160

12x=156

x=13

Now that we have x, we can plug them in to the expressions to find the measures of the given angles.

7(13)-4=87 degrees (angle WXZ)

5(13)+8=73 degrees (angle YXZ)