Question

A line parallel to Line MN contains (3, 1) and (-1, n). Find the value of n​

Answer 1

Explanation:

okay we can calculate for gradient.

• m=Y2-Y1 /X2-X1
• =n-1 /-1-3
• =n-1 /-4
• Therefore we can say gradient is equal to n-1 /-4 (m=n-1 /-4)
• n-1/-4=n-1 /-4
• we cross multiply
• 4(n-1)=--4(n-1)
• 4n-4=-4n+4
• we then solve for n
• 4n+4n=4+4
• 8n=8
• we then devide both side by 8 in order to get the value of n
• 8n/8=8/8
• n=0
• Therefore the line parallel to MN it is horizontaly lined