I need help please (algebra 1)

Question

asked Apr 1, 2023 234k views

1 Answer

AXheladini · Answer 1 · 2023-04-06T11:36:39+0000

Answer :

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Explanation :

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$\longrightarrow \sf \qquad {x}^(2) + 10x = 39$

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We can write it as,

$\longrightarrow \sf \qquad {x}^(2) + 10x - 39 = 0$

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We have to find the two numbers a and b such that,

$\longrightarrow \sf \qquad a + b = 10$

$\longrightarrow \sf \qquad a b = 39$

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Obviously, the two numbers are 3 and 13.

$\longrightarrow \sf \qquad {x}^(2) - 3x + 13x - 39 = 0$

$\longrightarrow \sf \qquad {x}(x - 3)+ 13(x - 3) = 0$

$\longrightarrow \sf \qquad ({x}+ 13)(x - 3) = 0$

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Whether, the value of x :

$\longrightarrow \sf \qquad {x}+ 13 = 0$

$\longrightarrow \pmb{\bf \qquad {x} = - 13}$

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Whether, the value of x :

$\longrightarrow \sf \qquad {x} - 3 = 0$

${\longrightarrow { \pmb{\bf \qquad {x} = 3}}}$

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So,