Question

A helium filled balloon has a pressure of 101 kPa and a temperature of 23 C. It is placed in a freezer where the temperature is 0 C. If the volume of the balloon remains constant, what is the new pressure of gas in the balloon?

Answer 1

P2 = 0.91 atm

Step-by-step explanation:

Using Gay-Lussac's Law for this question: P1/T1 = P2/T2

P1 = 101 kPa (dividing by 101.3 to convert to atm) = 0.99 atm

T1 = 23C (must be convert to Kelvin by plus 273.15) = 296.15K

T2 = 0C = 273.15K

P2 = ?

P1/T1 = P2/T2

(Multiply both sides by T2 to get rid of it).

273.15 x 0.99/296.15 = P2

P2 = 0.91 atm