224k views
4 votes
Solve the following compound inequality: −2(x + 4) + 10 < x − 7 OR −2x + 9 > 3(x + 8)

A: x < 3 or x > −3
B: x > 3 or x < −3
C: x < 7 or x > −3
D: x > 7 or x < −3

User Geoboy
by
8.3k points

1 Answer

1 vote

#1


\\ \sf{:}\!\implies -2(x+4)+10<x-7


\\ \sf{:}\!\implies -2x-8+10<x-7


\\ \sf{:}\!\implies x+2x>2+7


\\ \sf{:}\!\implies 3x>9


\\ \sf{:}\!\implies x>(9)/(3)


\\ \sf{:}\!\implies x>3

#2


\\ \sf{:}\!\implies -2x+9>3(x+8)


\\ \sf{:}\!\implies -2x+9>3x+24


\\ \sf{:}\!\implies -2x-3x>24-9


\\ \sf{:}\!\implies -5x>15


\\ \sf{:}\!\implies x>(15)/(-5)


\\ \sf{:}\!\implies x>-3

User Sonstabo
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories