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Write the equation of a line that is parallel to y=-3x-1 and passes through the point (-1,5)

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Write the equation of a line that is parallel to y=-3x-1 and passes through the point-example-1

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Answer:

y=-3x+8

Explanation:

Parallel lines on a graph must have the same slope AND different y-intercepts.

Therefore, the slope of the parallel line is also -3, but we need to find the y-intercept given the point (-1,5) so the line passes through it:

y=mx+b

y=-3x+b

5=-3(1)+b

5=-3+b

8=b

Therefore, the equation of the line would be y=-3x+8

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