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How many moles of oxygen will occupy a volume of 435 mL at 6780 torr and 28 °C?

1 Answer

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Answer:

n = 0.157

Step-by-step explanation:

To solve that question, we need to follow this equation: PV = nRT

V = 435ml (must be convert to L by ÷ by 1000) = 0.435 L

P = 6780 torr (must be convert to atm by ÷ by 760) = 8.92 atm

T = 28C (must convert to K by + 273.15) = 301.15 K

R = 0.08205

n = ?

PV = nRT

8.92 x 0.435 = n x 0.08205 x 301.15

3.88 = n x 24.7

Divided both sides by 24.7 (left n)

3.88/24.7 = n

0.157 = n

So 0.157 is the answer!

User Omry Yadan
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