Question

If Miguel has 9 nickels and quarters in his pocket, and they have a combined value of 125 cents, how many of each coin does he have?

PLEASE HELP!! IM GIVING 20 POINTS!!!! THANKSSSS

Answer 1

The answer 5 Nickels and 4 Quarters

Explanation:

The reason for this answer is simple I will do the math real quick.

So you have 5 nickels right so 5(5) would be your equation which equals 25.

Alright so for the quarters the equation is 4(25) which equals 100.

Now if you take 100 and add 25 to it you will get 125 which means problem solved hope this helped.

Answer 2

Let Miguel has n nickels. Then, he has 9 - n quarters. A nickel is worth 5 cents and a quarter is worth 25 cents. For his combination of coins, his value is 125 cents. Mathematically, this is expressed as

5(number of nickels) + 25(number of quarters) = 125

5n + 25(9-n) = 125

5n - 25n + (25)(9) = 125

-20n + 225 = 125

-20n = -100

20n = 100

n = 5

So, Miguel has 5 nickels and 9 - 5 = 4 quarters.