Answer:
Explanation:
Select the correct answer from each drop-down menu. A number is 5 more than 3 times another number. The sum of the two numbers is 33. As an equation, this is written x + 3x + 5 = 33, where x represents the smaller number. Plugin the numbers from the set {3, 5, 7, 9} to find the value of x. The value of x that holds true for the equation is 7. So, the smaller number is 7 and the larger number is 26 .
Find the value of x in x + 3x + 5 = 33, using {3, 5, 7, 9}
3:
x + 3x + 5 = 33
3 + 3(3) + 5 = 33
3 + 9 + 5 = 33
12 + 5 = 33
17 = 33
This is false, 17 does not equal to 33. <== wrong
5:
x + 3x + 5 = 33
5 + 3(5) + 5 = 33
5 + 15 + 5 = 33
20 + 5 = 33
25 = 33
This is false, 25 does not equal to 33. <== wrong
7:
x + 3x + 5 = 33
7 + 3(7) + 5 = 33
7 + 21 + 5 = 33
7 + 26= 33 <== (smaller number = 7, larger number = 26)
33 = 33
This is true, 33 does equal to 33. <== correct
9:
x + 3x + 5 = 33
9 + 3(9) + 5 = 33
9 + 27 + 5 = 33
36 + 5 = 33
41 = 33
This is false, 41 does not equal to 33. <== wrong
Not that we know that x = 7 (the smaller number), we need to find 3x (the larger number)
3x
3(7) = 21
Now, we add that to our original 5
21 + 5 = 26
Therefore, the smaller number is 7, while the larger number is 26.
Hope this helps!