Question

Find the perimeter of a rectangle if the length is
6y + 10 and the width is y - 3

Answer 1

Solution:-

We have been given to find out the perimeter of a rectangle who is having length (l) = 6y + 10 and width (w) = y - 3 i.e we have here,

• Length (l) = 6y + 10

• Width (w) = y - 3

The standard formula for calculating the perimeter of a rectangle is given by,

`\implies\rm{p = 2(l + w)}`

`\implies\rm{p = 2(6y + 10 + y - 3)}`

`\implies\rm{p = 2(6y + y + 10 - 3)}`

`\implies\rm{p = 2(7y + 7)}`

`\implies\rm{p = 14y + 14}`

• The perimeter of rectangle is 14y + 14 units.

Answer 2

Explanation:

Given that,

• Length = 6y + 10
• Width = y – 3

`\implies \sf Perimeter = 2(L + W) \\ \implies \sf P= 2(6y + 10 + y - 3) \: units \\ \implies \sf P= 2(7y +7) \: units \\ \implies \red{\sf P= 14y + 14 \: units} \\`

Therefore, perimeter is (14y + 14) units.