Answer:
Explanation:
Rewrite without absolute value for the given conditions:
1) y = |x−3|+|x+2|−|x−5|, if x > 5
y = x-3 + x + 2 - (x-5)
y = x + 4
2) y = |10-x|, if x<10
y = 10 - x
In both cases, the value of x is held to values that make the absolute value notation redundant, so they can be removed.
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Write the absolute value equations in the form x−b=c (where b is a number and c can be either number or an expression) that have the following solution sets:
I actually don't understand the question. Rewrite the above equations, or make new ones? Sorry.
1) All numbers such that x≤5
x≤5 kinda does it for me. X can be any number less than or equal to 5. Ta da. (?)
2) All numbers such that x≤−14.
x ≤ -14
Same comment. I'm not sure what is being asked.