Question

A gas at a constant pressure occupies 2.24 L at 52 C. If the sample is cooled United it takes up 1.66 L what is the new temperature?

A. 0.01 K
B. 0.01 C
C. 32 C
D. 241 K

PLS SHOW WORK

Answer 1

D is the answer!

Step-by-step explanation:

Using Charles's Law to solve this question: V1/T1 = V2/T2

V1 = 2.24L

T1 = 52C (covert to Kelvin by plus 273.15) = 325.15K

V2 = 1.66L

T2 = ?

V1/T1 = V2/T2 must change to V2×T1/V1 = T2

1.66 x 325.15/2.24 = V2

V2 = 240.96K ≈ 241K