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Cho x+y=3; xy=2 tính x2+y2

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Answer:

+, x + y = 3 => x = 3-y

thay vào xy =2 => (3-y)y = 2 <=> y^2 - 3y +2 = 0

<=> y=1 hoặc y = 2

=> x =2 hoặc x=1

=> x^2 + y^2 =5

User Evdokia
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