Answer:
Explanation:
Let Cyril = C
Let Alex = A
A + C = 50 (1)
A+5 = 4*C (2)
Solve (1) for A
A + C = 50 Solve for A
A + C-C = 50 - C
A = 50 - C
Substitute A into (2)
50 - C + 5 = 4C Add C to Both sides
50 + 5 = 4C + C Combine
55 = 5C Divide by 5
55/5 = 5C/5
C = 11
A + C = 50 Substitute for C
A + 11 = 50 Subtract 11 from both sides
A = 50 - 11
A = 39