Question

What is the length of segment AB to the nearest tenth?

Answer 1

4.9 units

Explanation:

Distance between 2 points= sqrt [(x-x)^2 + (y-y)^2

A= -4,2) and B= (1,4)

d = sqrt[(-4-1)^2 + (2-4)^2]

= sqrt (25+4)

= sqrt29

= 4.9 units