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Please help me please


\frac{ {5}^(x + 3 ) - 50 * {5}^(x - 2) }{41 * {5}^(x) }


1 Answer

8 votes

Answer:


\frac{ {5}^(x + 3) - 50 * {5}^(x - 2) }{41 * {5}^(x) } \\ \\ \frac{ ({5}^(x) * {5}^(3)) - 50 * ( {5}^(x) * {5}^( - 2) )}{41 * {5}^(x) }

Divide the numerator and denominator ÷ 5^x


\frac{ {5}^(3) - 50 * {5}^( - 2) }{41} \\ \\ \frac{ {5}^(3) - 50 * \frac{1}{ {5}^(2) } }{41 } \\ \\ \\ \frac{ {5}^(3) - \frac{50}{ {5}^(2) } }{41} \\ \\ \\ \frac{ {5}^(3) - (50)/(25) }{41} \\ \\ \\ \frac{ {5}^(3) - 2 }{41} \\ \\ \\ ((5 * 5 * 5) - 2)/(41) \\ \\ \\ (125 - 2)/(41) = (123)/(41) = 3

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