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The length of a rectangle is twice its width. If the area of the rectangle is 128 yd?, find its perimeter.
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The length of a rectangle is twice its width.

If the area of the rectangle is 128 yd?, find its perimeter.

User Ipd
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Answer:


let \: w \: be \: the \: width \: and \: l = 2w \\ area \: = 128 = (w)(2w) \\ 2{w}^(2) = 128 \\ {w}^(2) = 64 \\ w = 8 \: yd \\ l = 16 \\ perimeter \: = 2(8) + 2(16) = 48 \: yd

User Siddiq Abu Bakkar
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