Question

Y=-4(x-2)2+4
what is the x intercept

Answer 1

Solving for the x-intercepts of a Parabola given the Equation

Answer:

`x = 3` and
`x = 1`

Explanation:

`x`-intercepts are just the values
`x` when
`y = 0`.

Solving for
`x`:

`0 = -4(x -2)^2 +4 \\ -4(x -2)^2 +4 = 0 \\ -4(x -2)^2 = -4 \\ 4(x -2)^2 = 4 \\ (x-2)^2 = (4)/(4) \\ (x -2)^2 = 1 \\ x-2 = \pm \sqrt1 \\ x -2 = \pm 1 \\ x = \pm 1 +2`

Solving for the Positive Square Root:

`x = 1 +2 \\ x = 3`

Solving for the Negative Square Root:

`x = -1 +2 \\ x = 1`