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Find m∠D A-50° B-130° C-360° D-65° E-180°
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Find m∠D A-50° B-130° C-360° D-65° E-180°

Find m∠D A-50° B-130° C-360° D-65° E-180°-example-1
User Cosmitar
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1 Answer

6 votes

Answer:

D.65°

Explanation:

(2x-15)+(2x-15)+x+x=360 (quadrilateral angle)

6x-30=360

6x=390

x=65°

User Kevhender
by
3.9k points
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