Question

What's the range of the function y= -2(2)^x+2

Answer 1

Explanation:

Simply substitute the x and y values into the equation, Infinity is a number that gets closer & closer to zero and the y-intercept is always 2.

Infinity is a number that gets closer & closer to zero and the y-intercept is always 2.

y=-2(2)(-infity)+2

y=2