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Prove the following relations: cos²A + cos²A cot²A = cot²A
please help)):​

User Melikoth
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2 Answers

5 votes
the function is an identity
User Alvarado
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2 votes

Answer:

see explanation

Explanation:

Using the identities

1 + cot²x = cosec²x

cosec²x =
(1)/(sin^2x) , cotx =
(cosx)/(sinx)

Consider the left side

cos²A + cos²A cot²A ← factor out cos²A from each term

= cos²A(1 + cot²A)

= cos²A × cosec²A

= cos²A ×
(1)/(sin^2A)

=
(cos^2A)/(sin^2A)

= cot²A

= right side , thus proven

User Nir Hartmann
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