Question

Write an expression that will cause the following code to print "equal" if the value of sensorreading is "close enough" to targetvalue. Otherwise, print "not equal". Hint: use epsilon value 0. 1.

Ex: if targetvalue is 0. 3333 and sensorreading is (1. 0/3. 0),

output is:.

Answer 1

To determine if sensorreading is "close enough" to targetvalue, use a conditional statement that checks if the absolute difference between them is less than the specified epsilon value of 0.1. If true, print "equal"; otherwise, print "not equal".

Step-by-step explanation:

To write an expression that evaluates if the sensorreading is "close enough" to the targetvalue using an epsilon value of 0.1, you may use the following conditional statement:

if abs(sensorreading - targetvalue) < 0.1:
print("equal")
else:
print("not equal")

This code checks if the absolute difference between sensorreading and targetvalue is less than 0.1 (epsilon value), indicating they are close enough. If this condition is true, it prints "equal"; otherwise, it prints "not equal". In the example provided, where targetvalue is 0.3333 and sensorreading is the result of the expression (1.0/3.0), this code would output "equal" because the two values are close enough considering the epsilon.