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Help please, find the solution(s) for x In the equation below.

x2 + 7x = 8
OA. x = -1; x = 8
ОВ. x = 1; x = 8
OC. x = 1; x = 8
OD. x = -1; x = -8

Help please, find the solution(s) for x In the equation below. x2 + 7x = 8 OA. x = -1; x-example-1
User Iegik
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8.3k points

1 Answer

4 votes

Answer:

The correct answer is C, x = 1; x = -8



Explanation:

  • Quadratic formula:
    x=(-b\±√(b^2-4ac))/(2a)


x^2+7x=8


x^2+7x-8=0 <== a = 1, b = 7, c = -8


x=(-b\±√(b^2-4ac))/(2a) \\\\x=(-7\±√(7^2-4*1*-8))/(2*1) \\\\x=(-7\±√(7^2-4*-8))/(2) \\\\x=(-7\±√(49+32))/(2) \\\\x=(-7\±√(81))/(2) \\\\x=(-7\±9)/(2) \\\\x=(-7+9)/(2)\ \ and\ \ x=(-7-9)/(2) \\\\x=(2)/(2)\ \ and\ \ x=(-16)/(2) \\\\x=1\ \ and\ \ x-8\\\\x=1,\ x-8

Hope this helps!

User GenericUser
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