Question

A cannonball is shot from a cannon at a launch angle of 35 and an initial velocity of 147 m/s

Assuming No air resistance, what is the initial horizontal velocity of the cannonball.

A.)51.45 m/s
B.)147 m/s
C.)120 m/s
D.)9.8 m/s

Answer 1

The initial horizontal velocity of a cannonball shot from a cannon with a launch angle of 35° and an initial velocity of 147 m/s is approximately 120 m/s. Hence the correct answer is option C

Step-by-step explanation:

The initial horizontal velocity of a cannonball shot from a cannon can be calculated using the launch angle and initial velocity. In this case, the launch angle is 35° and the initial velocity is 147 m/s.

To find the initial horizontal velocity, you need to calculate the horizontal component of the initial velocity. This can be done using the formula:

Initial horizontal velocity = initial velocity * cos(launch angle)

Substituting the given values:

Initial horizontal velocity = 147 m/s * cos(35°)

Calculating this expression gives:

Initial horizontal velocity ≈ 120 m/s

Therefore, the correct answer is option C) 120 m/s.