Question

Refer to the attachment.​

Answer 1

`\huge \boxed{\mathbb{QUESTION} \downarrow}`

• 2x + 3y = 13.

`\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}`

First, let's solve for x.

`\sf \: 2 x + 3 y = 13`

Subtract 3y from both sides.

`\sf \: 2x=13-3y`

Divide both sides by 2.

`\sf(2x)/(2)=(13-3y)/(2) \\`

Dividing by 2 undoes the multiplication by 2.

`\boxed{ \boxed{\bf \: x=(13-3y)/(2) }}`

Now, let's solve for y.

`\sf \: 2 x + 3 y = 13`

Subtract 2x from both sides.

`\sf \: 3y=13-2x`

Divide both sides by 3.

`\sf \: (3y)/(3)=(13-2x)/(3) \\`

Dividing by 3 undoes the multiplication by 3.

`\boxed{ \boxed{ \bf \: y=(13-2x)/(3) }}`