Question

Math question about midpoint, pls help!

Answer 1

Using the midpoint formula,

`(x1 + x2)/(2) = 4 \\ (x1 + 2)/(2) = 4 \\ x1 + 2 = 4 * 2 \\ x1 + 2 = 8 \\ x1 = 8 - 2 \\ x1 = 6`

`(y1 + y2)/(2) = 4 \\ (y1 + 1)/(2) = 4 \\ y1 + 1 = 4 * 2 \\ y1 + 1 = 8 \\ y1 = 8 - 1 \\ y1 = 7`

Therefore,

Coordinates of B are (6 , 7)

Answer 2

(6,7)

Explanation:

let the co-ordinates of B are (x,y)

then
`(2+x)/(2) =4\\2+x=8\\x=8-2=6\\(1+y)/(2) =4\\1+y=8\\y=8-1=7\\`

so B is (6,7)