Question 1

An unknown organic compound composed of carbon, hydrogen and oxygen was analyzed and found to be 50. 84% c, 8. 53% h and the rest being oxygen. Write down the empirical formula for the compound?.

Question 2

$\boxed{\begin{array}c\boxed{\bf{Element}} &\boxed{\bf{Percentage}} &{\boxed{\bf{Atomic\:mass}} &\boxed{\bf{Constant\:in\:Sample}} &\boxed{\bf No\:of\:moles} &\boxed{\bf{Sample\:Ratio}} &\boxed{\bf{Sample\:whole\:no\:ratio}}\\ &&&&&& \\ \sf C &\sf 50.84 &\sf 12 &\sf 50.84g &\sf{(50.84)/(12)=4.2} &\sf {(4.2)/(3.6)=1.16} &\sf 1 \\ &&&&&&\\ \sf H &\sf 8.53 &\sf 1 &\sf 8.53g &\sf{(8.53)/(1)=8.53} &\sf{$(8.53)/(3.6)$}=2.37} &\sf 2 \\&&&&&&\\ \sf O &\sf 57.69 &\sf 16 &\sf 57.69g &\sf{(57.69)/(16)=3.6} &\sf{(3.6)/(3.6)=1} &\sf 1\end{array}}$

Now

Empirical formula is

$\\ \sf\bull\longmapsto C_1H_2O_1$

$\\ \sf\bull\longmapsto CH_2O$

An unknown organic compound composed of carbon, hydrogen and oxygen was analyzed and-example-1

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